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Combining Definite Integrals

Updated July 2026

Combining integrals with equal or contiguous ranges

Combining integrals with either equal or contiguous ranges. For example:

25f(x)dx+25g(x)dx=25[f(x)+g(x)]dx\int_{2}^{5} f(x)dx + \int_{2}^{5} g(x)dx = \int_{2}^{5}[f(x) + g(x)]dx

24f(x)dx+43f(x)dx=23f(x)dx\int_{2}^{4} f(x)dx + \int_{4}^{3} f(x)dx = \int_{2}^{3} f(x)dx

This section is really just a reiteration of what we have said earlier in these notes:

  • You can integrate term by term or all at once in an integral:

25f(x)dx+25g(x)dx=25[f(x)+g(x)]dx\int_{2}^{5} f(x) dx + \int_{2}^{5} g(x) dx = \int_{2}^{5}[f(x) + g(x)] dx

  • You can use the Fundamental Theorem of Calculus to simplify expressions:

24f(x)dx+43f(x)dx=23f(x)dx\int_{2}^{4} f(x) dx + \int_{4}^{3} f(x) dx = \int_{2}^{3} f(x) dx

It is worth checking that you have an intuitive grasp of both of these and also that you have a formal understanding of why they work.

We will use the Fundamental Theorem of Calculus to unpack the second statement:

24f(x)dx+43f(x)dx=23f(x)dx+34f(x)dx34f(x)dx\int_{2}^{4} f(x) dx + \int_{4}^{3} f(x) dx = \int_{2}^{3} f(x) dx + \int_{3}^{4} f(x) dx - \int_{3}^{4} f(x) dx =23f(x)dx= \int_{2}^{3} f(x) dx

Check you can see what we have done in the middle section.

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