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Theoretical Possibility Spaces for Probability

Updated August 2025

Probability calculation for the TMUA relies on constructing complete sample spaces. This lesson teaches you how to systematically list outcomes and build two-way grids for single and combined experiments. You will learn to use these spaces to calculate theoretical probabilities based on equally likely outcomes.

Core concept

A theoretical possibility space, or sample space, is the set SS of all distinct possible outcomes of an experiment. If all outcomes are equally likely, the probability of an event EE is P(E)=n(E)n(S)P(E) = \frac{n(E)}{n(S)}, where n(E)n(E) is the number of successful outcomes and n(S)n(S) is the total number of outcomes.

Introduction to Theoretical Probability

Probability is the mathematical measure of how likely an event is to occur. In the context of the TMUA and ESAT, we focus on theoretical probability, which is determined by analysing the physical or logical properties of an experiment rather than performing repeated trials. This analysis assumes that certain outcomes are equally likely. For example, when rolling a fair six sided die, we assume each number from 1 to 6 has the same chance of appearing.

Constructing Possibility Spaces

A possibility space, often called a sample space, is a comprehensive list or diagram showing every possible outcome of an experiment. To calculate probability correctly, the outcomes listed in your space must be mutually exclusive, meaning no two outcomes can happen at once, and exhaustive, meaning they cover every possibility. We use the symbol SS to represent the sample space and n(S)n(S) to represent the total count of outcomes in that space.

Single Experiments

For a single experiment, the possibility space is often a simple list. For a fair coin, the space is S={H,T}S = \{H, T\}, where HH denotes heads and TT denotes tails. For a standard die, S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}. In these cases, n(S)=2n(S) = 2 and n(S)=6n(S) = 6 respectively. The probability of any single outcome occurring is 1n(S)\frac{1}{n(S)}.

Combined Experiments and Sample Space Diagrams

When two or more experiments are performed together, such as rolling two dice or flipping three coins, constructing the possibility space requires a systematic approach to ensure no outcomes are missed or counted twice.

Two Way Grids

A two way grid, or sample space diagram, is the most effective way to represent the outcomes of two combined experiments. For example, if we roll two fair six sided dice, we can construct a grid where the rows represent the outcomes of the first die and the columns represent the outcomes of the second die.

This results in a 6 by 6 grid containing 36 unique outcomes. Each cell in the grid represents a pair of results, such as (1,1)(1, 1), (1,2)(1, 2), through to (6,6)(6, 6). Because the dice are independent and fair, every one of these 36 outcomes is equally likely.

Worked Example: The Sum of Two Dice

Consider rolling two fair dice and finding the probability that the sum of the scores is 9. First, we identify the total number of outcomes in the sample space, which is n(S)=36n(S) = 36. Next, we list the successful outcomes where the sum equals 9:

  1. Die 1 is 3 and Die 2 is 6: (3,6)(3, 6)
  2. Die 1 is 4 and Die 2 is 5: (4,5)(4, 5)
  3. Die 1 is 5 and Die 2 is 4: (5,4)(5, 4)
  4. Die 1 is 6 and Die 2 is 3: (6,3)(6, 3)

There are n(E)=4n(E) = 4 successful outcomes. The theoretical probability is calculated as:

P(Sum is 9)=n(E)n(S)=436=19P(\text{Sum is } 9) = \frac{n(E)}{n(S)} = \frac{4}{36} = \frac{1}{9}

Systematic Listing for Multi Stage Experiments

For experiments involving three or more stages, such as flipping three coins, a grid is not possible. Instead, we use systematic listing or tree diagrams. To list outcomes systematically, keep one variable constant while changing others. For three coin flips, the sample space is:

S={HHH,HHT,HTH,THH,HTT,THT,TTH,TTT}S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}

Here, n(S)=8n(S) = 8. Each outcome, such as HHTHHT, is distinct from HTHHTH. This distinction is vital because each outcome represents a different path through the experiment, and every path is equally likely.

Worked Example: Three Coins

Find the probability of obtaining exactly two heads when flipping three fair coins. From our listed sample space, we identify the outcomes with exactly two heads: {HHT,HTH,THH}\{HHT, HTH, THH\}. There are 3 such outcomes. Thus:

P(Exactly 2 heads)=38P(\text{Exactly 2 heads}) = \frac{3}{8}

Theoretical Probability with Tree Diagrams

Tree diagrams are another visual tool for constructing possibility spaces. Each branch represents a possible outcome of a single stage. By following every path from the start to the end of the tree, you can list the complete sample space. If each individual choice at every junction is equally likely, then every final path at the end of the tree is also equally likely. To calculate the probability, count the number of paths that satisfy your criteria and divide by the total number of paths.

Key takeaways

  • A possibility space must list every distinct outcome of an experiment exactly once.
  • For two combined experiments, use a two way grid to ensure all n×mn \times m outcomes are counted.
  • The outcomes used in the probability formula must be equally likely for the calculation to be valid.
  • Probabilities are always values between 0 and 1, where 1 represents a certainty.
  • Order often matters in combined experiments, such as (1,2)(1, 2) being different from (2,1)(2, 1) on two dice.
Tips

When rolling two dice, always imagine them as different colours, such as red and blue. This helps you remember that a Red 1 and Blue 2 is a different outcome from a Red 2 and Blue 1, which is essential for getting the correct denominator of 36.

Cautions

The most common error is failing to count outcomes correctly when listing them. For example, in the sum of two dice, many students forget that a sum of 7 can occur in 6 different ways, whereas a sum of 2 can only occur in 1 way. They are not equally likely as sums, even though the individual pairs are equally likely.

Insight

The number of outcomes in a combined experiment follows the fundamental counting principle. If one experiment has nn outcomes and a second has mm outcomes, the total combined possibility space has n×mn \times m outcomes. This is why a two way grid for two dice is 6 by 6.

Worked Examples

Example 1
A student is chosen at random from a class. Each student is equally likely to be
chosen.
Which of the following conditions is/are necessary for the probability that the
student wears glasses to equal
415\frac{4}{15}?
I Exactly 11 students in the class do not wear glasses.
II The number of students in the class is divisible by 3.
III The class contains 30 students, and 8 of them wear glasses.
A:none of them
B:I only
C:II only
D:III only
E:I and II only
F:I and III only
G:II and III only
H:I, II and III

Practice Questions

Practice Question 1
A pet shop has 4 female rabbits and xx male rabbits for sale.

A customer buys 2 of the rabbits, chosen at random, and each rabbit is equally likely to be chosen.

The probability that both the chosen rabbits are male is
13\frac{1}{3}.

What is the value of
xx?
A:2
B:4
C:6
D:8
E:9
F:11
G:12

Frequently asked questions

What does it mean for outcomes to be equally likely?

Outcomes are equally likely if each has the same theoretical chance of occurring. This is usually based on symmetry, such as a balanced die or a fair coin. If a die is biased, the six faces are not equally likely, and the standard 1/61/6 calculation would not apply.

Why is the sum of probabilities in a possibility space always equal to 1?

Since the possibility space is exhaustive, it covers 100 percent of the potential results. If you sum the probabilities of every individual outcome in the space SS, you must get n(S)n(S)=1\frac{n(S)}{n(S)} = 1.

How do I handle experiments where the outcomes are not equally likely?

If outcomes are not equally likely, you cannot simply count successful outcomes. Instead, you must assign specific probabilities to each individual outcome or use a weighted tree diagram. However, M7.6 specifically focuses on experiments where you can construct spaces of equally likely outcomes.

Does the order of results matter in a combined experiment?

Yes. In probability, we treat the first die and second die as distinct. If you are looking for a 1 and a 2, the outcomes (1,2)(1, 2) and (2,1)(2, 1) are two different ways this can happen. Ignoring order usually leads to an incorrect count of the total outcomes.

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