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Laws of Indices and Rational Exponents

Updated August 2025

This topic covers the essential rules for manipulating indices, including positive, negative, and fractional exponents. For the TMUA, understanding these laws is vital for simplifying algebraic expressions. This guide explains how rational exponents define roots and how zero and negative indices arise from consistent mathematical notation.

Core concept

Indices, or exponents, follow consistent rules such as am×an=am+na^m \times a^n = a^{m+n} and (am)n=amn(a^m)^n = a^{mn}, which allow us to define fractional powers as roots and negative powers as reciprocals for any positive base aa.

Defining the Notation

Indices, also known as powers or exponents, are a concise method for writing repeated multiplication. We start with the basic definition for a positive whole number mm: the expression ama^m represents the number aa multiplied by itself a total of mm times.

am=a×a×a××aa^m = a \times a \times a \times \dots \times a (mm factors of aa)

This notation allows us to derive our first rule. If we multiply ama^m by ana^n, we are multiplying a string of mm factors of aa by a string of nn factors of aa. The result is a single string of m+nm+n factors of aa:

am×an=(a××a)m times×(a××a)n times=am+na^m \times a^n = \underbrace{(a \times \dots \times a)}_{m \text{ times}} \times \underbrace{(a \times \dots \times a)}_{n \text{ times}} = a^{m+n}

RULE 1: am×anam+na^m \times a^n \equiv a^{m+n}

While this rule is derived using positive integers, we decide to extend it to all real numbers to ensure our notation remains consistent across mathematics.

Rational Exponents and Roots

To understand what a fractional power like a13a^{\frac{1}{3}} means, we apply Rule 1. If we multiply a13a^{\frac{1}{3}} by itself three times, we must add the exponents:

a13a13a13=a(13+13+13)=a1=aa^{\frac{1}{3}} a^{\frac{1}{3}} a^{\frac{1}{3}} = a^{(\frac{1}{3} + \frac{1}{3} + \frac{1}{3})} = a^1 = a

Since a13a^{\frac{1}{3}} multiplied by itself three times equals aa, it must be interpreted as the cube root of aa. This leads to our second rule for any positive integer nn:

RULE 2: a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}

Negative Indices and the Zero Power

We can determine the meaning of negative indices by exploring how Rule 1 applies to an expression like a3×a2a^3 \times a^{-2}. According to the rule:

a3×a2=a3+(2)=a1=aa^3 \times a^{-2} = a^{3+(-2)} = a^1 = a

To get aa from a3a^3, we must multiply by 1a2\frac{1}{a^2}. This leads to the definition of negative powers:

RULE 3: am=1ama^{-m} = \frac{1}{a^m}

Similarly, we can derive the value of a0a^0 by considering a2×a2a^2 \times a^{-2}:

a2×a2=a22=a0a^2 \times a^{-2} = a^{2-2} = a^0

Alternatively, using Rule 3:

a2×a2=a2×1a2=a2a2=1a^2 \times a^{-2} = a^2 \times \frac{1}{a^2} = \frac{a^2}{a^2} = 1

For consistency, we must define the zero power as follows:

RULE 4: a0=1a^0 = 1 (for a>0a > 0)

Further Laws and General Rational Exponents

Building on these foundations, we can establish the remaining laws of indices that are essential for the TMUA and ESAT:

RULE 5 (Division): am÷an=aman=am×an=amna^m \div a^n = \frac{a^m}{a^n} = a^m \times a^{-n} = a^{m-n}

RULE 6 (Powers of Powers): (am)n=amn(a^m)^n = a^{mn}

RULE 7 (General Rational Exponent): amn=(am)1n=amn=(a1n)m=(an)ma^{\frac{m}{n}} = (a^m)^{\frac{1}{n}} = \sqrt[n]{a^m} = (a^{\frac{1}{n}})^m = (\sqrt[n]{a})^m

When applying Rule 6, you must be extremely careful with notation. The expressions (am)n(a^m)^n and amna^{m^n} are not equivalent. For example:

(a3)2=a3×2=a6(a^3)^2 = a^{3 \times 2} = a^6, whereas a32=a9a^{3^2} = a^9.

Why Bases Must Be Positive

The index laws are generally applied where aa is a positive number. If the base aa is negative, rational powers can become problematic. For instance, (64)13=4(-64)^{\frac{1}{3}} = -4 is well defined in real numbers, but (64)12(-64)^{\frac{1}{2}} would require the square root of a negative number, which does not exist in the real number system. To avoid these inconsistencies, the specification focuses on positive aa.

Irrational Exponents

Although the specification focuses on rational exponents, these rules actually apply to irrational numbers as well. One way to visualise 232^{\sqrt{3}} is to consider the graph of y=2xy = 2^x. While calculating 2x2^x for rational xx gives a series of discrete points, these points are so close together that they form the appearance of a curve. The values for irrational xx are those that precisely fill the gaps to create a continuous, unbroken curve. Mathematically, these are found using the concept of limits, ensuring that the value of 232^{\sqrt{3}} lies between 2p2^p and 2q2^q, where pp and qq are rational numbers slightly smaller and larger than 3\sqrt{3} respectively.

Key takeaways

  • A fractional power represents a root, where a1na^{\frac{1}{n}} is the nthn^{\text{th}} root of aa.
  • A negative power indicates a reciprocal, so am=1ama^{-m} = \frac{1}{a^m}.
  • Any positive base raised to the power of zero equals 1.
  • When a power is raised to another power, the indices are multiplied: (am)n=amn(a^m)^n = a^{mn}.
  • Calculations with indices require consistent bases; am×ana^m \times a^n can be simplified, but am×bna^m \times b^n cannot.
Tips

When faced with complex index problems, try to express all bases as powers of the same prime number. For example, if a question involves 4, 8, and 16, rewrite them all as powers of 2 to allow for easier manipulation using the laws of indices.

Cautions

Do not confuse the laws for multiplication and addition. am×an=am+na^m \times a^n = a^{m+n}, but there is no simple law for am+ana^m + a^n. A common error is to try and add exponents when adding terms.

Insight

The transition from discrete counting (integer powers) to continuous functions (real powers) is a profound step in mathematics. It allows for the definition of exponential functions y=axy = a^x, which are unique because their rate of change is proportional to their value, a property fundamental to growth models in science and finance.

Worked Examples

Example 1
Find the coefficient of the x4x^4 term in the expansion of x2(2x+1x)6x^2 \left(2x + \frac{1}{x}\right)^6
A:15
B:30
C:60
D:120
E:240

Practice Questions

Practice Question 1
Given that y=(13x)22x32y = \frac{(1-3x)^2}{2x^{\frac{3}{2}}}, which one of the following is a correct expression for dydx\frac{dy}{dx}?
A:94x12+32x3234x52\frac{9}{4}x^{-\frac{1}{2}} + \frac{3}{2}x^{-\frac{3}{2}} - \frac{3}{4}x^{-\frac{5}{2}}
B:94x1232x32+34x52\frac{9}{4}x^{-\frac{1}{2}} - \frac{3}{2}x^{-\frac{3}{2}} + \frac{3}{4}x^{-\frac{5}{2}}
C:94x1232x3234x52\frac{9}{4}x^{-\frac{1}{2}} - \frac{3}{2}x^{-\frac{3}{2}} - \frac{3}{4}x^{-\frac{5}{2}}
D:94x12+32x32+34x52-\frac{9}{4}x^{-\frac{1}{2}} + \frac{3}{2}x^{-\frac{3}{2}} + \frac{3}{4}x^{-\frac{5}{2}}
E:94x12+32x3234x52-\frac{9}{4}x^{-\frac{1}{2}} + \frac{3}{2}x^{-\frac{3}{2}} - \frac{3}{4}x^{-\frac{5}{2}}
F:94x1232x3234x52-\frac{9}{4}x^{-\frac{1}{2}} - \frac{3}{2}x^{-\frac{3}{2}} - \frac{3}{4}x^{-\frac{5}{2}}

Frequently asked questions

Is 000^0 equal to 1?

In most elementary contexts, a0=1a^0 = 1 is defined for a>0a > 0. The case of 000^0 is more complex and is often considered an indeterminate form in calculus, though in some areas of discrete mathematics, it is defined as 1.

Does (am)n(a^m)^n always equal amna^{mn}?

Yes, this is Rule 6. However, you must distinguish this from amna^{m^n}, where the exponent mm is raised to the power nn before the base aa is considered. For instance, 232=29=5122^{3^2} = 2^9 = 512, while (23)2=26=64(2^3)^2 = 2^6 = 64.

Can I use these rules if the base is a fraction?

Absolutely. For example, (xy)2=(yx)2=y2x2(\frac{x}{y})^{-2} = (\frac{y}{x})^2 = \frac{y^2}{x^2}. The rules apply to any positive real base, whether integer, fraction, or irrational.

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