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Graphs of Functions and Differentiation

Updated September 2025

Learn how to use calculus to determine the shape of a graph for university admissions tests. This page covers finding and classifying stationary points using first and second derivatives, and identifying intervals where a function is strictly increasing or decreasing. A vital skill for sketching accurate polynomial curves.

Core concept

The derivative f(x)f'(x) represents the gradient of the tangent to the curve y=f(x)y=f(x) at any point. By identifying where f(x)=0f'(x)=0, f(x)>0f'(x)>0, or f(x)<0f'(x)<0, we can determine the location of stationary points and the intervals of growth or decay for a function.

Differentiation is a powerful tool for determining the qualitative and quantitative features of a function's graph. While basic algebra tells us where a graph crosses the axes, calculus tells us about its turning points and general direction.

Stationary Points

A stationary point occurs when the tangent to a curve is horizontal. At such a point, the gradient is zero, meaning the rate of change of yy with respect to xx is null. Mathematically, we find stationary points by solving the equation:

dydx=0\frac{dy}{dx} = 0

Once we have identified the xx values that satisfy this equation, we must classify the points as local maxima or local minima. There are several techniques for this.

Worked Example: Classifying Points on a Cubic

Consider the cubic function y=2x33x212x+6y = 2x^3 - 3x^2 - 12x + 6. To find the stationary points, we first differentiate the expression:

dydx=6x26x12\frac{dy}{dx} = 6x^2 - 6x - 12

Setting this equal to zero and factorising:

6(x2x2)=06(x^2 - x - 2) = 0

6(x2)(x+1)=06(x - 2)(x + 1) = 0

This gives us stationary points at x=2x = 2 and x=1x = -1. Because this cubic has a positive coefficient for the x3x^3 term, we expect the maximum to be on the left and the minimum on the right. Thus, the maximum occurs at x=1x = -1 and the minimum at x=2x = 2.

The Second Derivative Test

A more formal method for classification uses the second derivative, d2ydx2\frac{d^2y}{dx^2}, which tells us how the gradient itself is changing.

  1. If dydx=0\frac{dy}{dx} = 0 and d2ydx2>0\frac{d^2y}{dx^2} > 0, the point is a local minimum. This is because the gradient is increasing, turning from negative to positive.

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  1. If dydx=0\frac{dy}{dx} = 0 and d2ydx2<0\frac{d^2y}{dx^2} < 0, the point is a local maximum. The gradient is decreasing, turning from positive to negative.

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In our cubic example y=2x33x212x+6y = 2x^3 - 3x^2 - 12x + 6, the second derivative is d2ydx2=12x6\frac{d^2y}{dx^2} = 12x - 6.

At x=2x = 2: d2ydx2=12(2)6=18\frac{d^2y}{dx^2} = 12(2) - 6 = 18. Since 18>018 > 0, it is a minimum.

At x=1x = -1: d2ydx2=12(1)6=18\frac{d^2y}{dx^2} = 12(-1) - 6 = -18. Since 18<0-18 < 0, it is a maximum.

Logical Nuances

It is important to note that the conditions d2ydx2>0\frac{d^2y}{dx^2} > 0 or d2ydx2<0\frac{d^2y}{dx^2} < 0 are sufficient but not necessary. For example, at the minimum of y=x4y = x^4, dydx=0\frac{dy}{dx} = 0 and d2ydx2=0\frac{d^2y}{dx^2} = 0. This shows that if the second derivative is zero, the test is inconclusive and the point could still be a maximum, minimum, or a point of inflexion.

Increasing and Decreasing Functions

Calculus allows us to define precisely when a function is always moving "upwards" or "downwards" on a graph.

Strictly Increasing Functions

Intuitively, a strictly increasing function is one where the yy value always gets greater as the xx value gets greater. A sufficient condition for this using differentiation is:

If f(x)>0f'(x) > 0 for all xx in an interval, then the function is strictly increasing on that interval.

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Strictly Decreasing Functions

A strictly decreasing function is one where the yy value always gets less as the xx value gets greater. The sufficient condition is:

If f(x)<0f'(x) < 0 for all xx in an interval, then the function is strictly decreasing on that interval.

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Note that we cannot say the reverse: if a function is strictly increasing, it does not mean f(x)>0f'(x) > 0 for all xx. Some functions may have corners where the derivative is not defined, yet they are still strictly increasing. However, for the smooth polynomial functions typical of the TMUA, looking for f(x)>0f'(x) > 0 or f(x)<0f'(x) < 0 is the primary method.

Points of Inflexion

While detailed examination of inflexions is excluded, you should have a qualitative understanding that they represent a point where the curve changes concavity. In the graph of y=x3y = x^3, the point at the origin is a horizontal point of inflexion because f(0)=0f'(0) = 0, but the graph does not turn back: it increases before and after the point.

Key takeaways

  • Stationary points are located by solving f(x)=0f'(x) = 0.
  • Use the second derivative f(x)f''(x) to classify points: f(x)>0f''(x) > 0 is a minimum, f(x)<0f''(x) < 0 is a maximum.
  • A function is strictly increasing on an interval where f(x)>0f'(x) > 0.
  • A function is strictly decreasing on an interval where f(x)<0f'(x) < 0.
  • Calculus conditions like f(x)>0f''(x) > 0 are sufficient for classification, but not necessary, as shown by functions like y=x4y = x^4.
Tips

In the exam, if you find stationary points for a cubic, you can often classify them just by looking at the coefficient of x3x^3. A positive x3x^3 cubic goes from -\infty to ++\infty, so the first stationary point encountered from the left must be a maximum and the second a minimum.

Cautions

Be careful when differentiating fractional or negative powers of xx before finding stationary points. Always simplify the expression into a sum of powers first to avoid errors in the power rule nxn1n x^{n-1}.

Insight

The relationship between f(x)f'(x) and the shape of f(x)f(x) is a local property. By finding where f(x)f'(x) changes sign, you are effectively finding the 'boundaries' of the different regions of the graph's behaviour, allowing you to piece together the global shape of the function.

Frequently asked questions

What happens if both the first and second derivatives are zero?

If f(x)=0f'(x) = 0 and f(x)=0f''(x) = 0, the second derivative test is inconclusive. The point could be a maximum (like y=x4y = -x^4), a minimum (like y=x4y = x^4), or a point of inflexion (like y=x3y = x^3). You must check the gradient or yy values on either side of the point to classify it.

What is the difference between a stationary point and a turning point?

A turning point is a stationary point where the function changes direction (a maximum or a minimum). A stationary point is any point where f(x)=0f'(x) = 0, which includes horizontal points of inflexion where the function does not actually "turn".

Does f(x)0f'(x) \geq 0 mean a function is strictly increasing?

No. f(x)0f'(x) \geq 0 allows for intervals where the function is constant (flat). For a function to be strictly increasing, the yy value must strictly increase as xx increases. The sufficient condition we use is f(x)>0f'(x) > 0.

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