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Fundamental Trigonometric Identities for the TMUA

Updated August 2025

Mastering the identities tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} and sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 is a requirement for the TMUA. These tools allow you to simplify trigonometric expressions and solve complex equations by reducing them to a single trigonometric function, particularly in quadratic contexts.

Core concept

The fundamental identities tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} and sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 are relationships derived from the definitions of trigonometric ratios and Pythagoras' Theorem. They are valid for all real values of θ\theta for which the functions are defined.

Defining Trigonometric Identities

There are many ways to define trigonometric functions. Usually, we first meet trigonometry in relation to right-angled triangles. If we use this approach, the identities we use in the TMUA can be derived directly from the basic ratios of opposite, adjacent, and hypotenuse.

The Relationship between Tangent, Sine, and Cosine

It is sufficient for the TMUA to realise that the relationship between these three functions comes from the standard definitions provided when you first learn trigonometry:

  1. sinθ=OH\sin \theta = \frac{O}{H}

  2. cosθ=AH\cos \theta = \frac{A}{H}

  3. tanθ=OA\tan \theta = \frac{O}{A}

From these, it becomes obvious that tanθ\tan \theta can be expressed as a ratio of sinθ\sin \theta and cosθ\cos \theta:

tanθ=OA=O/HA/H=sinθcosθ\tan \theta = \frac{O}{A} = \frac{O/H}{A/H} = \frac{\sin \theta}{\cos \theta}

This identity is particularly useful when you need to solve equations that contain both sine and cosine terms but no squared terms, as it allows you to convert the equation into one involving only tangent.

The Pythagorean Identity: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

The second identity is fundamentally a version of Pythagoras' Theorem. Consider a right-angled triangle where the hypotenuse is 1 unit long. By the definitions of sine and cosine, the opposite side has length sinθ\sin \theta and the adjacent side has length cosθ\cos \theta.

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Applying Pythagoras' Theorem (a2+b2=c2a^2 + b^2 = c^2) to this triangle gives:

(sinθ)2+(cosθ)2=12(\sin \theta)^2 + (\cos \theta)^2 = 1^2

Which is written in standard notation as:

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

Universal Applicability and the CAST Diagram

While these identities are easily visualised using acute angles in a right-angled triangle, it is vital to notice that they apply to ANY angle θ\theta, whether it is acute, obtuse, reflex, or negative.

You can justify why these identities apply universally by considering the 'CAST' style diagrams. In these diagrams, the hypotenuse HH is always taken as a positive value (often H=1H = 1). The signs of sinθ\sin \theta and cosθ\cos \theta change as the signs of the adjacent (AA) and opposite (OO) sides change across the four quadrants, but the relationships tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} and sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 remain consistent due to the algebraic properties of coordinates and the definition of a circle.

Practical Use in Solving Equations

In the TMUA, these identities are often used to reduce an equation to a single trigonometric function. For example, in equations involving cos2x\cos^2 x and sinx\sin x, you can substitute cos2x=1sin2x\cos^2 x = 1 - \sin^2 x. This creates a quadratic equation in terms of sinx\sin x, which can then be factorised and solved using standard quadratic techniques.

Key takeaways

  • The identity tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} is always true provided cosθ0\cos \theta \neq 0.
  • The identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 is a trigonometric form of Pythagoras' Theorem.
  • Identities apply to all angles, not just those between 0 and 90 degrees.
  • Rearranging sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 allows you to substitute sin2θ\sin^2 \theta for 1cos2θ1 - \cos^2 \theta and vice versa.
Tips

When you see a trigonometric equation with a squared term and a linear term of a different function (e.g., cos2x\cos^2 x and sinx\sin x), always look to use sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 to convert the squared term. This is the most common way to form a solvable quadratic.

Cautions

Be careful when dividing by cosθ\cos \theta to create a tanθ\tan \theta term. You must ensure that cosθ0\cos \theta \neq 0. If cosθ=0\cos \theta = 0 is a potential solution to the original equation, dividing by it will cause you to lose that solution.

Insight

These identities are the bridge between geometry and algebra. While they originate in the geometry of triangles, they allow us to treat trigonometric functions as algebraic variables, which is why we can solve trigonometric equations using the same tools we use for polynomials.

Worked Examples

Example 1
The non-zero real number cc is such that the equation cosx=c\cos x = c has two solutions for 0<x<32π0 < x < \frac{3}{2}\pi.
How many solutions of the equation
cos22x=c2\cos^2 2x = c^2 are there in the range 0<x<32π0 < x < \frac{3}{2}\pi?
A:2
B:3
C:4
D:6
E:7
F:8

Practice Questions

Practice Question 1
Find the fraction of the interval 0θπ0 \leq \theta \leq \pi for which the inequality (sin(2θ)12)(sinθcosθ)0(\sin(2\theta) - \frac{1}{2})(\sin \theta - \cos \theta) \geq 0 is satisfied.
A:112\frac{1}{12}
B:16\frac{1}{6}
C:14\frac{1}{4}
D:512\frac{5}{12}
E:712\frac{7}{12}
F:34\frac{3}{4}
G:56\frac{5}{6}
H:1112\frac{11}{12}

Frequently asked questions

Can I use these identities for angles in both degrees and radians?

Yes. These identities are fundamental properties of the functions themselves and are independent of the unit used to measure the angle.

Is sin2θ\sin^2 \theta the same as sinθ2\sin \theta^2?

No. sin2θ\sin^2 \theta means (sinθ)×(sinθ)(\sin \theta) \times (\sin \theta), whereas sinθ2\sin \theta^2 means the sine of the squared angle. Brackets or the standard sin2θ\sin^2 \theta notation should be used to avoid ambiguity.

When should I use tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} in an equation?

This is most useful when an equation has sinθ\sin \theta and cosθ\cos \theta terms of the same power. By dividing through by cosθ\cos \theta, you can often create a single tanθ\tan \theta term.

Does sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 always equal exactly 1?

Yes, for any real number θ\theta, this is an absolute identity. It is a mathematical constant derived from the geometry of the unit circle.

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