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Solving Linear Inequalities in One and Two Variables

Updated August 2025

Mastering linear inequalities is vital for the TMUA, particularly for coordinate geometry and algebraic reasoning. This guide covers solving single-variable inequalities, representing solution sets on number lines, and identifying feasible regions on two-dimensional graphs. You will learn the critical rules for reversing inequality signs and how to combine multiple constraints.

Core concept

An inequality describes the relative size of two expressions using symbols like <,>,,<, >, \leq, \geq. Solving them involves the same algebraic operations as equations, with the essential distinction that multiplying or dividing by a negative value reverses the direction of the inequality sign.

Symbols and Labelling Conventions

Inequalities are represented by four primary symbols. For a single variable xx, the representation on a number line follows specific conventions to indicate whether the boundary value is included in the solution set.

  1. << (Less than): x<4x < 4 defines all values less than but not including 4. On a number line, this is shown with an open circle at 4.
  2. >> (Greater than): x>4x > 4 defines all values greater than but not including 4. This is also shown with an open circle at 4.
  3. \leq (Less than or equal to): x4x \leq 4 defines all values less than 4, including 4 itself. This is shown with a solid circle at 4.
  4. \geq (Greater than or equal to): x4x \geq 4 defines all values greater than 4, including 4. This is shown with a solid circle at 4.

Inequalities in Two Variables

When dealing with two variables, solution sets are represented as shaded regions on a coordinate graph. The boundary is defined by the equivalent linear equation.

  • Dotted Lines: Used for strict inequalities (<< or >>). This indicates that the points on the line itself are not part of the solution.
  • Solid Lines: Used for inclusive inequalities (\leq or \geq). This indicates that the points on the line are included.

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The shaded area above shows the region x<yx < y. Notice the dotted line for the boundary x=yx = y.

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In this graph, the region xyx \geq y is shown with a solid boundary line. When solving problems involving multiple inequalities, it is often clearer to shade the unwanted region and leave the required region unshaded. It is crucial to state clearly which method you are using.

Simplifying Inequalities

If x<yx < y, specific rules apply when manipulating the expression:

  • Addition and Subtraction: Adding or subtracting a real number from both sides leaves the sign unchanged. For example: x4<y4x - 4 < y - 4.
  • Positive Multipliers: Multiplying or dividing by a positive real number leaves the sign unchanged. For example: 34x<34y\frac{3}{4}x < \frac{3}{4}y.
  • Inversion: If xx and yy are both positive or both negative, inverting both sides changes the direction of the sign. For example: 1x>1y\frac{1}{x} > \frac{1}{y}.
  • Negative Multipliers: Multiplying or dividing by a negative real number changes the direction of the sign. For example: 34x>34y-\frac{3}{4}x > -\frac{3}{4}y.

Combining Inequalities

Combined inequalities take the form a<b<ca < b < c. Both symbols must point in the same direction. Notation such as a<b>ca < b > c is mathematically incorrect.

  • The set x>7x > -7 and x10x \leq 10 is written as 7<x10-7 < x \leq 10.
  • The set x<7x < -7 and x10x \leq 10 simply reduces to x<7x < -7.
  • If inequalities do not overlap or define a continuous range, such as x<7x < -7 and x10x \geq 10, they cannot be combined into a single continuous statement.
  • Statements like 7<x<10-7 < x < -10 are incorrect because 7-7 is not less than 10-10.

Worked Examples: Single Variable

Example 1: Simple Linear Inequality Solve 3x4>83x - 4 > 8 and represent it on a number line.

  1. Add 4 to both sides: 3x>123x > 12.
  2. Divide by 3: x>4x > 4. This is represented by a number line with an open circle at 4 and an arrow pointing to the right.

Example 2: Two-sided Linear Inequality Solve 203x4>820 \geq 3x - 4 > 8.

  1. Add 4 to all three sections: 243x>1224 \geq 3x > 12.
  2. Divide all three sections by 3: 8x>48 \geq x > 4. On a number line, place an unfilled circle at 4 and a filled circle at 8, joining them with a line.

Example 3: Complicated Variable Expression Solve 3x5<2(2+3x)3x - 5 < 2(2 + 3x).

  1. Multiply out the bracket: 3x5<4+6x3x - 5 < 4 + 6x.
  2. Subtract 6x6x from both sides: 3x5<4-3x - 5 < 4.
  3. Add 5 to both sides: 3x<9-3x < 9.
  4. Multiply by 1-1 and reverse the sign: 3x>93x > -9.
  5. Divide by 3: x>3x > -3.

Worked Examples: Finding Ranges

Overlapping Ranges: Find the range for 3x4<83x - 4 < 8 and 3x2>83x - 2 > -8.

  • From the first: 3x<12x<43x < 12 \rightarrow x < 4.
  • From the second: 3x>6x>23x > -6 \rightarrow x > -2.
  • Combined: 2<x<4-2 < x < 4.

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Contained Ranges: Find the range for 3x4<83x - 4 < 8 and 3x2<83x - 2 < -8.

  • From the first: x<4x < 4.
  • From the second: x<2x < -2.
  • The valid range for both is simply x<2x < -2.

Non-overlapping Ranges: Find the range for 3x+2<103x + 2 < -10 and 3x4>83x - 4 > 8.

  • From the first: x<4x < -4.
  • From the second: x>4x > 4.
  • There is no range where both are valid.

Simultaneous Inequalities in Two Variables

To solve 3x+4y123x + 4y \leq 12 graphically:

  1. Draw the boundary line 3x+4y=123x + 4y = 12.
  2. Test a point, such as (0,0)(0,0). Since 3(0)+4(0)123(0) + 4(0) \leq 12 is true, the region containing (0,0)(0,0) is the solution set.
  3. Use a solid line for the boundary.

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To solve multiple inequalities like 3x+4y123x + 4y \leq 12, yx+6y \geq x + 6, and x>7x > -7:

  • Draw each boundary line.
  • Shade out the unwanted regions for each constraint.
  • The remaining unshaded region is the solution.

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Key takeaways

  • Always reverse the inequality sign when multiplying or dividing both sides by a negative number.
  • Use open circles for strict inequalities (<< and >>) and solid circles for inclusive ones (\leq and \geq) on number lines.
  • Strict inequalities in two variables are represented by dotted boundary lines, while inclusive ones use solid lines.
  • To identify the correct region on a graph, test a simple point like (0,0)(0,0) in the inequality expression.
  • Combined inequalities like a<x<ba < x < b must have signs pointing the same way and must be mathematically consistent.
Tips

For TMUA questions involving shading, always clearly label your axes and boundary lines. Testing the origin (0,0)(0,0) is the fastest way to determine which side of a line to shade, provided the line does not pass through the origin itself.

Cautions

A very common error is forgetting to flip the inequality sign when multiplying by a negative. Always double check your final step, especially in algebraic rearrangements.

Insight

The solution to a linear inequality in two variables is a half plane. When multiple inequalities are applied, the intersection forms a convex feasible region, a concept fundamental to linear programming and optimization.

Worked Examples

Example 1
The graphs of y=x2+5x+6y = x^2 + 5x + 6 and y=mx3y=mx-3, where mm is a constant, are plotted on the same set of axes.
Given that the graphs do not meet, what is the complete range of possible values of
mm?
A:1<m<11-1<m< 11
B:m<1,m>11m<-1, m > 11
C:11<m<11-\sqrt{11} < m < \sqrt{11}
D:m<11,m>11m<-\sqrt{11}, m> \sqrt{11}
E:11<m<1-11<m<1
F:m<11,m>1m<-11, m> 1

Practice Questions

Practice Question 1
The angle x is measured in radians and is such that 0xπ0 \le x \le \pi.

The total length of any intervals for which
1tanx1-1 \le \tan x \le 1 and sin2x0.5\sin 2x \ge 0.5 is
A:π12\frac{\pi}{12}
B:π6\frac{\pi}{6}
C:π4\frac{\pi}{4}
D:π3\frac{\pi}{3}
E:5π12\frac{5\pi}{12}
F:π2\frac{\pi}{2}
G:5π6\frac{5\pi}{6}

Frequently asked questions

When should I use a dotted line instead of a solid line on a graph?

A dotted line is used for strict inequalities, such as y>xy > x or y<xy < x. A solid line is used when the inequality is inclusive, such as yxy \geq x or yxy \leq x.

What happens if I divide an inequality by a negative number?

You must reverse the direction of the inequality sign. For example, 2x<10-2x < 10 becomes x>5x > -5 after dividing by 2-2.

Can I combine x>5x > 5 and x<2x < 2 into one statement?

No. These ranges do not overlap and do not form a single continuous interval. They must be written as two separate statements.

Is it possible for a set of simultaneous inequalities to have no solution?

Yes. If the shaded regions for the different inequalities do not overlap at any point on the graph, there is no set of coordinates that satisfies all conditions simultaneously.

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