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Circle Geometry Vocabulary and Properties for the TMUA

Updated August 2025

Mastering circle geometry requires both a precise vocabulary and an understanding of coordinate equations. This page defines essential terms like chord, tangent, and segment, while exploring the algebraic representation of circles. You will learn to identify centres, calculate radii, and apply core circle theorems essential for the TMUA.

Core concept

A circle is defined as the set of all points (x,y)(x, y) that are a constant distance rr (the radius) from a fixed point (a,b)(a, b) (the centre), represented by the equation (xa)2+(yb)2=r2(x - a)^2 + (y - b)^2 = r^2.

Basic Circle Vocabulary

To succeed in the TMUA, you must be fluent in conventional circle terminology. A circle consists of several distinct parts:

  1. Centre: The fixed point from which all points on the circumference are equidistant.
  2. Radius: The constant distance from the centre to any point on the circle.
  3. Diameter: A straight line passing through the centre, connecting two points on the circumference. It is exactly twice the length of the radius.
  4. Circumference: The perimeter or boundary of the circle.
  5. Chord: A straight line segment joining any two points on the circumference.
  6. Tangent: A straight line that touches the circumference at exactly one point and is perpendicular to the radius at that point.
  7. Arc: A portion of the circumference. An arc smaller than a semicircle is a minor arc, while one larger is a major arc.
  8. Sector: The region bounded by two radii and an arc (resembling a pizza slice). A minor sector has an angle less than 180 degrees, while a major sector is larger.
  9. Segment: The region bounded by a chord and an arc. A minor segment is the smaller part created by the chord, and the major segment is the larger part.

The Equation of a Circle

Imagine drawing a circle of radius 1 on the xyxy plane with its centre at the origin. All points on this circle are a distance of 1 from the origin. Using Pythagoras' theorem, we can express this as x2+y2=12x^2 + y^2 = 1^2. Any (x,y)(x, y) satisfying this equation is on the circle.

img-22.jpeg

If we increase the radius to rr, the equation becomes x2+y2=r2x^2 + y^2 = r^2.

img-23.jpeg

To move the centre to a different point (a,b)(a, b), we use a translation. Pythagoras' theorem tells us that the distance between (x,y)(x, y) and (a,b)(a, b) is rr, leading to the standard form:

(xa)2+(yb)2=r2(x - a)^2 + (y - b)^2 = r^2

img-24.jpeg

Identifying Centre and Radius

You must be able to identify the radius and centre quickly. For example, (x2)2+(y3)2=25(x - 2)^2 + (y - 3)^2 = 25 has a centre at (2,3)(2, 3) and a radius of 5 (since 52=255^2 = 25). Circles are often written in the expanded form x2+y2+cx+dy+e=0x^2 + y^2 + cx + dy + e = 0. To find the centre and radius from this form, you must complete the square for both xx and yy.

Example: Finding the centre and radius

Find the centre and radius of x2+y2+4x+2y12=0x^2 + y^2 + 4x + 2y - 12 = 0.

  1. Collect xx and yy terms: x2+4x+y2+2y12=0x^2 + 4x + y^2 + 2y - 12 = 0.
  2. Complete the square: (x+2)24+(y+1)2112=0(x + 2)^2 - 4 + (y + 1)^2 - 1 - 12 = 0.
  3. Rearrange: (x+2)2+(y+1)2=17(x + 2)^2 + (y + 1)^2 = 17.

The centre is (2,1)(-2, -1) and the radius is 17\sqrt{17}.

Caution on non-circles

Not every equation of the form x2+y2+ax+by+c=0x^2 + y^2 + ax + by + c = 0 is a circle. For instance, x2+y24x6y+20=0x^2 + y^2 - 4x - 6y + 20 = 0 simplifies to (x2)2+(y3)2=7(x - 2)^2 + (y - 3)^2 = -7. Since the sum of squares cannot be negative, no real (x,y)(x, y) values satisfy this, so it is not a circle.

Tangents and Intersections

A line can intersect a circle twice, once (tangent), or not at all.

Example: Finding a tangent

Find the values of cc for which y=2x+cy = 2x + c is tangent to the circle (x3)2+(y2)2=9(x - 3)^2 + (y - 2)^2 = 9.

img-25.jpeg

  1. Substitute the line into the circle: (x3)2+(2x+c2)2=9(x - 3)^2 + (2x + c - 2)^2 = 9.
  2. Expand and rearrange into a quadratic in xx: 5x2+2(c7)x+(c2)2=05x^2 + 2(c - 7)x + (c - 2)^2 = 0.
  3. For a tangent, the discriminant must be zero (b24ac=0b^2 - 4ac = 0): 4(c7)220(c2)2=04(c - 7)^2 - 20(c - 2)^2 = 0.
  4. Solve for cc: c7=±5(c2)c - 7 = \pm \sqrt{5}(c - 2). This gives two values for cc, representing the two possible tangent lines.

Circle Properties and Theorems

You are expected to know and apply the following geometric properties:

  1. Chords: The perpendicular from the centre to a chord bisects the chord.
  2. Tangents: The tangent at any point is perpendicular to the radius at that point.
  3. Angles at the Centre: The angle subtended by an arc at the centre is twice the angle subtended at the circumference.
  4. Semicircles: The angle in a semicircle is a right angle.
  5. Segments: Angles in the same segment are equal.
  6. Cyclic Quadrilaterals: Opposite angles in a cyclic quadrilateral add to 180 degrees.
  7. Alternate Segment Theorem: The angle between a tangent and a chord is equal to the angle in the alternate segment.

When solving problems, use angle chasing by looking for isosceles triangles formed by radii, or add auxiliary lines such as diameters or chords to reveal hidden relationships.

Key takeaways

  • The standard equation of a circle with centre (a,b)(a, b) and radius rr is (xa)2+(yb)2=r2(x - a)^2 + (y - b)^2 = r^2.
  • To find the centre and radius from the general form x2+y2+cx+dy+e=0x^2 + y^2 + cx + dy + e = 0, you must complete the square for both variables.
  • A tangent to a circle intersects it at exactly one point, meaning the discriminant of the resulting simultaneous equation must be zero.
  • Circle theorems, such as the angle at the centre being twice the angle at the circumference, are powerful tools for angle chasing in geometric problems.
Tips

When identifying a circle from an equation like 2x2+2y24x8y19=02x^2 + 2y^2 - 4x - 8y - 19 = 0, remember to divide the entire equation by the coefficient of x2x^2 (in this case, 2) before attempting to complete the square.

Cautions

A common error is mistaking the constant in (xa)2+(yb)2=k(x - a)^2 + (y - b)^2 = k for the radius. The radius is actually k\sqrt{k}. Always check that k>0k > 0, otherwise the equation represents no real points.

Insight

The alternate segment theorem is often the most difficult to spot in complex diagrams. Look for the 'triangle' inside the circle where one vertex meets the point of contact between a tangent and the circle.

Worked Examples

Example 1
A square PQRS is drawn above the x-axis with the side PQ on the x-axis.
P is the point (–5, 0) and Q is the point (1, 0).
A circle is drawn inside the square with diameter equal in length to the side of the square.
Which one of the following is an equation of the circle?
A:x2+y24x+6y+4=0x^2 + y^2 - 4x + 6y + 4 = 0
B:x2+y24x+6y+9=0x^2 + y^2 - 4x + 6y + 9 = 0
C:x2+y2+4x6y+4=0x^2 + y^2 + 4x - 6y + 4 = 0
D:x2+y2+4x6y+9=0x^2 + y^2 + 4x - 6y + 9 = 0
E:x2+y26x4y+9=0x^2 + y^2 - 6x - 4y + 9 = 0
F:x2+y26x+4y+4=0x^2 + y^2 - 6x + 4y + 4 = 0
G:x2+y2+6x4y+4=0x^2 + y^2 + 6x - 4y + 4 = 0
H:x2+y2+6x+4y+9=0x^2 + y^2 + 6x + 4y + 9 = 0

Practice Questions

Practice Question 1
A rectangle PQRS is drawn inside a circle, with its vertices on the circumference of the circle.

Exam diagram


[diagram not to scale]

The ratio of the length of PQ to the length of QR is 2:1

The area of the rectangle PQRS is 96 cm².

What is the radius, in cm, of the circle?
A:6\sqrt{6}
B:3
C:323\sqrt{2}
D:2152\sqrt{15}
E:464\sqrt{6}
F:12
G:12212\sqrt{2}
H:8158\sqrt{15}

Frequently asked questions

What is the difference between a sector and a segment?

A sector is a region bounded by two radii and an arc (like a slice of pie). A segment is a region bounded by a chord and an arc (the 'cap' of a circle).

How do I know if a line is a tangent to a circle using algebra?

Substitute the equation of the line into the equation of the circle. If the resulting quadratic equation has exactly one real solution (the discriminant b24ac=0b^2 - 4ac = 0), the line is a tangent.

Does the term radius refer to a line or a length?

It refers to both: the line segment connecting the centre to the circumference and the length of that segment.

Why is the angle in a semicircle always 90 degrees?

This is a special case of the theorem that the angle at the centre is twice the angle at the circumference. Since the angle at the centre of a diameter is 180 degrees, the angle at the circumference must be 90 degrees.

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